Process the image on the website using Pilgram
I'm completely zero in programming and I'm just trying to take the first steps. I think the solution to my problem is pretty simple, but I can't find it. I want to have 2 fields in the Images model: image and processed_image.
I am using Django 5.1.4, Python 3.13.1, Pillow 11.1.0 and Pilgram 1.2.1
I want the user to upload an image to a form on the website. The image was processed using pilgram. And then the processed image was saved in the processed_image field. But when I save the picture, the processed_image field in the database remains empty. Please tell me what my mistake is?
postcard/images/models.py
from django.db import models
from PIL import Image
import pilgram
import os
from django.urls import reverse
from django.contrib.auth.models import User
from .services.utils import unique_slugify
class Images(models.Model):
user = models.ForeignKey(User, on_delete=models.CASCADE, related_name='user')
title = models.CharField('Название', max_length=255)
slug = models.SlugField("URL", max_length=255, unique=True, db_index=True)
image = models.ImageField('Изображение', upload_to="images/%Y/%m/%d/")
processed_image = models.ImageField('Отработанное изображение', upload_to="processed/%Y/%m/%d/", blank=True, null=True)
time_create = models.DateTimeField('Дата создания', auto_now_add="True")
def __str__(self):
return self.title
def save(self, *args, **kwargs):
super().save(*args, **kwargs)
if self.image:
self.process_image()
def process_image(self):
img_path = self.image.path
img = Image.open(img_path)
img = pilgram._1977(img)
processed_path = os.path.join(os.path.dirname(img_path),f"processed_{os.path.basename(img_path)}")
img.save(processed_path)
self.processed_image = processed_path
super().save(update_fields=['processed_image'])
class Meta:
verbose_name = 'Картинка'
verbose_name_plural = 'Картинки'
ordering = ['-time_create', 'title']
def get_absolute_url(self):
return reverse('image', kwargs={'image_slug': self.slug})
def save(self, *args, **kwargs):
"""
Сохранение полей модели при их отсутствии заполнения
"""
if not self.slug:
self.slug = unique_slugify(self, self.title)
super().save(*args, **kwargs)
postcard/images/views.py
from django.shortcuts import render, redirect
from django.urls import reverse_lazy
from django.views.generic import ListView, DetailView, CreateView, UpdateView, DeleteView
from .forms import ImageForm
from .models import Images
class ImagesList(ListView):
paginate_by = 20
model = Images
template_name = 'images/image_list.html'
context_object_name = 'images'
class UploadImage(CreateView):
form_class = ImageForm
template_name = 'images/upload.html'
success_url = reverse_lazy('upload_image')
def form_valid(self, form):
form.instance.user = self.request.user
return super(UploadImage, self).form_valid(form)
class ImageDone(DetailView):
model = Images
template_name = 'images/image_done.html'
slug_url_kwarg = 'image_slug'
context_object_name = 'image'
postcard/images/forms.py
from django import forms
from .models import *
class ImageForm(forms.ModelForm):
class Meta:
model = Images
fields = ['title', 'image']
postcard/images/urls.py
from django.urls import path
from .views import *
urlpatterns = [
path('upload_image', UploadImage.as_view(), name='upload_image'),
path('image/<slug:image_slug>/', ImageDone.as_view(), name='image'),
path('image_list', ImagesList.as_view(), name='image_list'),
]
postcard/images/admin.py
from django.contrib import admin
from .models import Images
@admin.register(Images)
class ImagesAdmin(admin.ModelAdmin):
prepopulated_fields = {'slug': ('title',)}