Django: Как назначить кнопку для приема информации и сохранения()

Есть ли способ для кнопки сделать следующее: когда пользователь нажимает кнопку, она берет user.username текущего пользователя и автоматически заполняет форму BookInstance из models.py и сохраняет ее в базе данных.

From models.py :

class BookInstance(models.Model):
    id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False)
    book = models.ForeignKey("Book", on_delete=models.RESTRICT, null=True)
    imprint = models.CharField(max_length=200, blank=True, null=True)
    due_back = models.DateField(blank=True, null=True)
    borrower = models.ForeignKey(
        User, on_delete=models.SET_NULL, blank=True, null=True)

    LOAN_STATUS = (
        ('m', 'Maintenance'),
        ('o', 'On Loan'),
        ('a', 'Available'),
        ('r', 'Reserved')
    )

    status = models.CharField(
        max_length=1, choices=LOAN_STATUS, blank=True, default='a')

    class Meta:
        ordering = ['due_back']

    def __str__(self):
        return f'{self.id} - {self.book.title}'

    def get_absolute_url(self):
        return reverse("catalog:book_list")

class Book(models.Model):

    title = models.CharField(max_length=50)
    author = models.ForeignKey(
        'Author', on_delete=models.SET_NULL, null=True)
    summary = models.TextField(
        max_length=500, help_text="Enter brief description")
    isbn = models.CharField('ISBN', max_length=13, unique=True)
    genre = models.ManyToManyField(Genre, help_text="Select genre")

    language = models.ForeignKey(
        "Language", on_delete=models.SET_NULL, null=True)

    def __str__(self):
        return self.title

    def get_absolute_url(self):
        return reverse("catalog:book_detail", kwargs={"pk": self.pk})

Это мое от моего views.py :

def borrowBook(request, pk):

    context = {
        'book_instance': BookInstance.objects.all()
    }

    success_url = reverse_lazy('catalog:index')
    if request.method == "POST":
        form = BorrowForm(request.POST or None)
        if form.is_valid():
            book_instance.id = BookInstance.objects.get(pk=pk)
            book_instance.book = BookInstance.objects.get(book=book)
            book_instance.borrower = request.user
            book_instance.status = 'o'
            book_borrowed_count = BookInstance.objects.filter(
                owner=request.user).count()
            if book_borrowed_count < 4:
                book_instance = form.save(commit=False)
                book_instance.save()
            else:
                print("Maximum limit reached!")
            return redirect('catalog:index')

    return render(request, 'catalog/book_detail.html', {'form': form})

вот из моего BorrowForm из forms.py :

class BorrowForm(forms.ModelForm):
    class Meta:
        model = BookInstance
        fields = '__all__'

вот мое от моего urls.py :

path("book_list/book/<int:pk>/borrow", views.borrowBook, name="borrowBook"),

Я также попробовал использовать CBV здесь:

class BorrowBookView(PermissionRequiredMixin, CreateView):
    permission_required = 'login'
    model = BookInstance
    fields = '__all__'
    template_name = 'catalog/borrow_form.html'
    success_url = reverse_lazy('catalog:index')

    def post(self, request, *args, **kwargs):
        book_instance.id = BookInstance.objects.get(pk=pk)
        book_instance.book = BookInstance.objects.get(book=book)
        book_instance.borrower = request.user
        book_instance.status = 'o'
        book_instance = form.save(commit=False)
        book_instance.save()

CBV путь от urls.py :

path("book_list/book/<int:pk>/borrow/",
         views.BorrowBookView.as_view(), name="book_borrow"),

Вот как я реализовал кнопку, используя предложения отсюда:

                <form action="#" method="post">
                    {% csrf_token %}
                    <button 
                        type="submit" 
                        class="btn btn-dark flex-shrink-0 " 
                        value="{{ book.id }}">Borrow
                    </button>

но когда я нажимаю, кажется, что ничего не сохраняется в базе данных и просто всплывают ошибки, хотя я могу реализовать кнопку или функцию из моих представлений неправильно. Спасибо и признателен за любую оказанную помощь.

from django.contrib.auth.mixins import LoginRequiredMixin
from django.views import View
from django.contrib import messages
from django.urls import reverse
from django.http import HttpResponseRedirect
from django.shortcuts import get_object_or_404

from .models import BookInstance

class BorrowBook(LoginRequiredMixin, View):
    def get(self, request, *args, **kwargs):
        book_id = kwargs['pk']
        available_books = BookInstance.objects.filter(book__pk=book_id, status='a')
        return render(request, 'borrow_book.html', {'available_books': available_books})


    def post(self, request, *args , **kwargs):
        book_instance_id = request.POST['id']
        obj = get_object_or_404(BookInstance, id=book_instance_id)
        obj.status = 'r'
        obj.borrower = request.user
        # Maybe also update due_back data
        # obj.due_back = ...
        obj.save()
        messages.success(request, "Your book is reserved.")
        # I used the redirection to the same template
        # But you probably want to send the user somewhere else
        return HttpResponseRedirect(reverse('core:borrow-book', kwargs={'pk': 1}))

{% extends 'base.html' %}

{% block content %}
    {% if messages %}
    <ul class="messages">
        {% for message in messages %}
        <li{% if message.tags %} class="{{ message.tags }}"{% endif %}>{{ message }}</li>
        {% endfor %}
    </ul>
    {% endif %}

    {% for instance in available_books %}
    <form action="{% url 'core:borrow-book' instance.book.id %}" method="POST">
        {% csrf_token %}
        <input type="hidden" name="id" value="{{instance.id}}">
        <p>{{instance.book}}</p>
        <p>{{instance.book.language.name}}</p>
        <input type="submit" value="Borrow this book.">
    </form>
        
    {% endfor %}
{% endblock content %}

from django.urls import path
from core import views

app_name = 'core'

urlpatterns = [
    path("book_list/book/<int:pk>/borrow/", views.BorrowBook.as_view(), name="borrow-book"),
]