Django Текущий путь, newapp/1, не соответствует ни одному из этих путей

При попытке получить доступ к http://192.168.68.106:8000/newapp/1

Using the URLconf defined in test_01.urls, Django tried these URL patterns, in this order:

1.admin/                                **working fine
2.polls/                                **working fine
3.newapp [name='index']                 **working fine
4.newapp testform/ [name='testform']    **NOT working
5.newapp thanks/                        **NOT working
6.newapp 1/                             **Not working

The current path, newapp/1, didn’t match any of these.

следуя руководству по опросам в официальном документе ( https://docs.djangoproject.com/en/4.0/intro/tutorial01/), приложение polls работает нормально. и индекс newapp также работает. но когда я пытаюсь расширить приложение, создавая новые страницы для него (а именно testform/, thanks/, 1/), я получаю 404 в ответ.

views.py

from django.shortcuts import render

from django.template import loader
from django.http import HttpResponse, HttpResponseRedirect
from django.urls import reverse
from django.views import generic
from .forms import TestForm


class IndexView(generic.View):
        template_name = "newapp/index.html"

        def get(self, request, *args, **kwargs):
                context = {
                        /mycontexts
                        }

                return render(request, self.template_name, context)


class TestForm(generic.edit.FormView):
        form = TestForm
        template_name = "newapp/form_test.html"
        success = "/thanks/"

def thanks(request):
        return HttpResponse("thanks!")

def test1(request):
        return HttpResponse("good")

urls.py

from . import views

app_name = "newapp"
urlpatterns = [
        path("", views.IndexView.as_view(), name="index"),
        path("testform/", views.TestForm.as_view(), name="testform"), 
        path("thanks/", views.thanks), #I tried to use a function instead of class based view, but failed to produce a success result
        path("1", views.test1),  #I didn't miss a backslash here, it was intentionally removed to see if it made a difference

]

Что меня озадачило, так это то, что фреймворк понимает, что у меня есть представление и ссылки на testform, thanks и 1. но они не могут быть доступны вручную через браузер?

обновление: urls.py

"""test_01 URL Configuration

The `urlpatterns` list routes URLs to views. For more information please see:
    https://docs.djangoproject.com/en/4.0/topics/http/urls/
Examples:
Function views
    1. Add an import:  from my_app import views
    2. Add a URL to urlpatterns:  path('', views.home, name='home')
Class-based views
    1. Add an import:  from other_app.views import Home
    2. Add a URL to urlpatterns:  path('', Home.as_view(), name='home')
Including another URLconf
    1. Import the include() function: from django.urls import include, path
    2. Add a URL to urlpatterns:  path('blog/', include('blog.urls'))
"""
from django.contrib import admin
from django.urls import include, path

urlpatterns = [
        path('admin/', admin.site.urls),
        path("polls/", include("polls.urls")),
        path("newapp", include("newapp.urls"))
]

Я не думаю, что это проблема с проектом urls.py, поскольку я могу получить доступ к индексной странице нового приложения.

from django.contrib import admin
from django.urls import include, path

urlpatterns = [
        path('admin/', admin.site.urls),
        path("polls/", include("polls.urls")),
        path("newapp/", include("newapp.urls"))
]

from . import views

app_name = "newapp"
urlpatterns = [
        path("", views.IndexView.as_view(), name="index"),
        path("testform/", views.TestForm.as_view(), name="testform"), 
        path("thanks/", views.thanks), #I tried to use a function instead of class based view, but failed to produce a success result
        path("1/", views.test1),  

]

from django.contrib import admin
from django.urls import include, path

urlpatterns = [
        path('admin/', admin.site.urls),
        path("polls/", include("polls.urls")),
        path("newapp/", include("newapp.urls"))
]

from . import views

app_name = "newapp"
urlpatterns = [
        path("", views.IndexView.as_view(), name="index"),
        path("testform/", views.TestForm.as_view(), name="testform"), 
        path("thanks/", views.thanks), #I tried to use a function instead of class based view, but failed to produce a success result
        path("1/", views.test1),  

]