Как сделать запрос в Django, который подсчитывает объекты внешнего ключа?
Привет всем!
Новичок в Django, и запутался, помощь приветствуется! Я пытаюсь создать таблицу, типа:
Organization | Total amount of appeals | Amount of written form appeals | Amount of oral form appeals |
---|---|---|---|
Organization 1 | 3 | 1 | 2 |
Organization 2 | 2 | 1 | 1 |
У вас три модели:
class Organization(models.Model):
organization_name = models.CharField(max_length=50)
class AppealForm(models.Model):
form_name = models.CharField(max_length=50)
class Appeal(models.Model):
organization = models.ForeignKey(Organization, on_delete=models.CASCADE)
appeal_form = models.ForeignKey(AppealForm, on_delete=models.CASCADE)
applicant_name = models.CharField(max_length=150)
Объекты модели Организация:
organization_name |
---|
Organization 1 |
Organization 2 |
Объекты модели AppealForm:
form_name |
---|
In written form |
In oral form |
Объекты модели Appeal:
organization | appeal_form | applicant_name |
---|---|---|
Organization 1 | In written form | First and Last name |
Organization 1 | In oral form | First and Last name |
Organization 1 | In oral form | First and Last name |
Organization 2 | In written form | First and Last name |
Organization 2 | In oral form | First and Last name |
Как сделать сложный запрос, чтобы получить информацию из модели Appeal? И поместить в точные поля таблицы выше?:(
)Вы можете сделать запрос с помощью:
from django.db.models import Count, Q
organizations = Organization.objects.annotate(
).annotate(
total=Count('appeal'),
total_written=Count('appeal', filter=Q('appeal__appeal_form__form_name='in written form')),
total_oral=Count('appeal', filter=Q('appeal__appeal_form__form_name='in oral form'))
)
Затем мы можем отобразить Organization
s с помощью:
<table>
<thead>
<tr><th>Organization</th><th>Total amount of appeals</th><th>Amount of written form appeals</th><th>Amount of oral form appeals</th></tr>
</thead>
<tbody>
{% for organization in organizations %}
<tr><td>{{ organization.organization_name }}</td><td>{{ organization.total }}</td><td>{{ organization.total_written }}</td><td>{{ organization.total_oral }}</td></tr>
{% endfor %}
</tbody>
</table>
Я знаю, что мое решение не самое лучшее. Но результат - это то, что вы искали.
views.py
:
from django.shortcuts import render
from .models import Appeal, Organization
from django.db.models import Count
def index(request):
on = Organization.objects.values_list('organization_name').distinct()
x = Appeal.objects.values(
"organization__organization_name", "appeal_form__form_name"
).annotate(total=Count("appeal_form__form_name"))
out = {}
for name in on:
out[name[0]] = {}
for el in x:
for k in out.keys():
if not out[k].get('total'):
out[k]['total'] = 0
if el.get('organization__organization_name') == k:
out[k].update({el.get('appeal_form__form_name'):el.get('total')})
out[k]['total']+=el.get('total')
context = {
"appeal": out,
}
return render(request, "pages/index.html", context)
index.html
:
<table>
<tr>
<th>Organization</th>
<th>Appeal Form</th>
<th>Total amount of appeals </th>
<th>Amount of written form appeals</th>
<th>Amount of oral form appeals</th>
</tr>
{% for k,v in appeal.items %}
<tr>
<td> {{ k }} </td>
{% for form_name ,form_count in v.items %}
<td align="center">{{ form_count}}</td>
{% endfor %}
</tr>
{% endfor %}