What would be the best way to return the result of asynchronous task to Django views?

I am building a Djano app that processes image in a Celery task. A post inside the view method handles the input and triggers the task. Inside the task, I create a model instance based on the processed image. In the same view, I wanted to return a response of the de-serialization of the model instance. What is the best way to throw this response? Should a frontend expect this on another url? How can I signal my app that the model instance is ready to be served?

# models.py
class Image(models.Model):
    name = models.CharField(max_length=50, blank=True)
    ...

# tasks.py
@shared_task
def long_running_function(user, data):

    image = Image.objects.create()
    ...
    return image # ?

# views.py
class RequestImage(APIView):

    def post(self, request):
        ...
        image = celery_task_example.delay(
            request.user.id, 
            request.data
        )
        # if image is ready
        serializer = ImageSerializer(image)
        return Response(serializer.data)

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